MerLean-example

40 Def 23: Balanced Product Chain Complex

Definition 517 H-Equivariant Chain Complex
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Let \(H\) be a group. An \(H\)-equivariant chain complex over \(\mathbb {F}_2\) consists of:

  • an underlying chain complex \(C_\bullet \) over \(\mathbb {F}_2\),

  • for each degree \(i \in \mathbb {Z}\), a representation \(\rho _i : H \to \operatorname {GL}_{\mathbb {F}_2}(C_i)\) (i.e., a left \(\mathbb {F}_2[H]\)-module structure on \(C_i\)),

  • an equivariance condition: for all \(i, j \in \mathbb {Z}\) and \(h \in H\),

    \[ \partial ^{i \to j} \circ \rho _i(h) = \rho _j(h) \circ \partial ^{i \to j}, \]

    i.e., the differential \(\partial : C_i \to C_j\) intertwines the \(H\)-actions.

Definition 518 Balanced Product Object

Let \(C\) and \(D\) be \(H\)-equivariant chain complexes. For integers \(p, q \in \mathbb {Z}\), the balanced product object at \((p,q)\) is

\[ (C \boxtimes _H D)_{p,q} \; =\; C_p \otimes _H D_q, \]

the balanced product (coinvariants of \(C_p \otimes _{\mathbb {F}_2} D_q\) under the diagonal \(H\)-action) of the representations \(\rho ^C_p\) and \(\rho ^D_q\).

Definition 519 Horizontal Differential of Balanced Product

Let \(C\) and \(D\) be \(H\)-equivariant chain complexes. The horizontal differential

\[ \partial ^h_{p,p',q} : C_p \otimes _H D_q \longrightarrow C_{p'} \otimes _H D_q \]

is induced by \(\partial ^C_{p \to p'} \otimes \operatorname {id}_{D_q}\) on the balanced product. This is well-defined on coinvariants by the \(H\)-equivariance of \(\partial ^C\).

Definition 520 Vertical Differential of Balanced Product

Let \(C\) and \(D\) be \(H\)-equivariant chain complexes. The vertical differential

\[ \partial ^v_{p,q,q'} : C_p \otimes _H D_q \longrightarrow C_p \otimes _H D_{q'} \]

is induced by \(\operatorname {id}_{C_p} \otimes \partial ^D_{q \to q'}\) on the balanced product. This is well-defined on coinvariants by the \(H\)-equivariance of \(\partial ^D\).

Definition 521 Balanced Product Double Complex

Let \(C\) and \(D\) be \(H\)-equivariant chain complexes. The balanced product double complex \(C \boxtimes _H D\) is the double complex over \(\mathbb {F}_2\) with:

  • objects \((C \boxtimes _H D)_{p,q} = C_p \otimes _H D_q\),

  • horizontal differential \(\partial ^h = \partial ^C \otimes _H \operatorname {id}_D\) (decreasing \(p\)),

  • vertical differential \(\partial ^v = \operatorname {id}_C \otimes _H \partial ^D\) (decreasing \(q\)).

This forms a valid double complex: \((\partial ^h)^2 = 0\), \((\partial ^v)^2 = 0\), and \(\partial ^h \circ \partial ^v = \partial ^v \circ \partial ^h\).

Definition 522 Balanced Product Complex

Let \(C\) and \(D\) be \(H\)-equivariant chain complexes. The balanced product complex

\[ C \otimes _H D \; =\; \operatorname {Tot}(C \boxtimes _H D) \]

is the total complex of the balanced product double complex \(C \boxtimes _H D\).

Theorem 523 Balanced Product Double Complex Object

For all \(p, q \in \mathbb {Z}\), the object of the balanced product double complex at \((p,q)\) satisfies

\[ (C \boxtimes _H D)_{p,q} = C_p \otimes _H D_q. \]
Proof

This holds by reflexivity, as the definition of \(\operatorname {balancedProductDoubleComplex}\) sets the object at \((p,q)\) to be \(\operatorname {bpObj}(p,q) = C_p \otimes _H D_q\) definitionally.

Theorem 524 Vertical Differential Formula

For all \(p, q \in \mathbb {Z}\), the vertical differential of the balanced product double complex satisfies

\[ \partial ^v_{p,q} \; =\; \partial ^v_{p,q,q-1} : C_p \otimes _H D_q \to C_p \otimes _H D_{q-1}, \]

i.e., it is induced by \(\operatorname {id}_{C_p} \otimes \partial ^D_{q \to q-1}\).

Proof

This holds by reflexivity, as \(\operatorname {dv}\) at \((p,q)\) in the balanced product double complex is defined as the linear map underlying \(\operatorname {bpDv}(p, q, q-1)\).

Theorem 525 Horizontal Differential Formula

For all \(p, q \in \mathbb {Z}\), the horizontal differential of the balanced product double complex satisfies

\[ \partial ^h_{p,q} \; =\; \partial ^h_{p,p-1,q} : C_p \otimes _H D_q \to C_{p-1} \otimes _H D_q, \]

i.e., it is induced by \(\partial ^C_{p \to p-1} \otimes \operatorname {id}_{D_q}\).

Proof

This holds by reflexivity, as \(\operatorname {dh}\) at \((p,q)\) in the balanced product double complex is defined as the linear map underlying \(\operatorname {bpDh}(p, p-1, q)\).

Lemma 526 Balanced Product Complex is Nonempty

For every \(n \in \mathbb {Z}\), the degree-\(n\) component of the balanced product complex \(C \otimes _H D\) is nonempty (as it contains the zero element).

Proof

We exhibit the zero element \(0 \in (C \otimes _H D)_n\), which witnesses that the type is nonempty.