Documentation

MerLeanBpqc.Lemmas.Lem_4_KunnethBalancedProduct

Lemma 4: Künneth Formula for Balanced Products #

Let H be a finite group of odd order, and let C, D be H-equivariant chain complexes over 𝔽₂. Then there is an isomorphism $$H_n(C \otimes_H D) \cong \bigoplus_{p+q=n} H_p(C) \otimes_H H_q(D)$$

The proof uses:

  1. Over 𝔽₂ with |H| odd, coinvariants (-)_H is an exact functor
  2. Exactness means coinvariants commutes with homology
  3. The ordinary Künneth formula (Thm_1) gives H_n(C ⊗ D) ≅ ⊕ H_p(C) ⊗ H_q(D)
  4. Applying coinvariants: H_n(C ⊗_H D) ≅ ⊕ H_p(C) ⊗_H H_q(D)

Main Definitions #

Main Results #

Induced H-action on homology #

Since the differentials are H-equivariant, H acts on cycles Z_p = ker ∂_p and boundaries B_p = im ∂_{p+1}. The induced action on H_p(C) = Z_p / B_p is well-defined.

H acts on cycles Z_p(C) = ker ∂_p, since ∂(h · z) = h · ∂(z) = h · 0 = 0 for z ∈ ker ∂.

Equations
  • One or more equations did not get rendered due to their size.
Instances For

    H acts on boundaries B_p(C) = im ∂_{p+1}, since for b = ∂(x), h · b = h · ∂(x) = ∂(h · x) ∈ im ∂.

    Equations
    • One or more equations did not get rendered due to their size.
    Instances For

      The boundaries submodule of cycles inherits an H-action from cyclesAction, compatible with the inclusion.

      Equations
      • One or more equations did not get rendered due to their size.
      Instances For

        The induced H-action on homology H_p(C) = Z_p / B_p. Since H acts on both Z_p and B_p compatibly, the quotient action is well-defined.

        Equations
        Instances For

          Balanced Künneth summands #

          @[reducible, inline]

          The summand of the balanced Künneth decomposition at index p: H_p(C) ⊗_H H_{n-p}(D), the balanced product of homology groups. Defined as coinvariants of the tensor product representation, which avoids universe constraints of the balancedProduct abbreviation.

          Equations
          Instances For
            @[reducible, inline]

            The balanced Künneth direct sum ⊕_{p : ℤ} H_p(C) ⊗_H H_{n-p}(D).

            Equations
            Instances For

              Exactness of coinvariants in characteristic 2 with odd order group #

              Over 𝔽₂ with H of odd order, |H| = 1 in 𝔽₂, so the averaging map a(v) = ∑_h h·v is an idempotent splitting: V = V^H ⊕ ker(a). This makes (-)_H ≅ (-)^H an exact functor.

              The cardinality of H is invertible in 𝔽₂ when |H| is odd.

              Equations
              Instances For

                Main theorem: Künneth formula for balanced products #

                Künneth Formula for Balanced Products (Lemma 4).

                For H a finite group of odd order and C, D H-equivariant chain complexes over 𝔽₂, $$H_n(C \otimes_H D) \cong \bigoplus_{p+q=n} H_p(C) \otimes_H H_q(D).$$

                The proof proceeds as follows:

                1. Over 𝔽₂ with |H| odd, |H| = 1 in 𝔽₂, so the averaging map a = ∑_h ρ(h) is an idempotent with im(a) = V^H. This gives V = V^H ⊕ ker(a), making coinvariants (-)_H ≅ (-)^H an exact functor (Def_22, balancedProductInvariantsEquiv).
                2. Since (-)_H is exact, it commutes with homology: H_n((C ⊗ D)_H) ≅ (H_n(C ⊗ D))_H.
                3. By the Künneth formula (Thm_1): H_n(C ⊗ D) ≅ ⊕_{p+q=n} H_p(C) ⊗ H_q(D).
                4. Taking coinvariants and using (-)_H commutes with finite direct sums: (H_n(C ⊗ D))_H ≅ ⊕_{p+q=n} (H_p(C) ⊗ H_q(D))_H = ⊕_{p+q=n} H_p(C) ⊗_H H_q(D).

                Accepted as axiom: the full proof requires showing that the balanced product complex C ⊗_H D equals the coinvariants of the tensor product complex (C ⊗ D)_H at the chain complex level (connecting totalComplex from Def_10 with balancedProductComplex from Def_23), and then constructing the chain of isomorphisms through exact functor arguments. This infrastructure for coinvariant-homology interchange and for connecting the two total complex constructions is not available in Mathlib.

                Satisfiability witnesses #

                Witness: the premises of kunnethBalancedProduct are satisfiable. The trivial group H = Unit has odd order |H| = 1, and any chain complexes (e.g., the zero complex) are equivariant.

                Witness: the balanced Künneth summand is nonempty (contains 0).

                Witness: the balanced Künneth sum is nonempty (contains 0).